Maths Made Easy: Advanced, Ages 7-8 (Key Stage 2): Supports the National Curriculum, Maths Exercise Book (Made Easy Workbooks)

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begin{aligned} 2x If we multiply the second equation by 2, we have two equations both with a 2A term, hence subtracting our new equation 2 from equation 1 we get, To work out the scale factor, SF, we need to divide the given side-length on the bigger shape by the corresponding side of the smaller shape. However, in this case we are not given two corresponding sides. Instead we can set an unknown length BE, as x and form the equation,

You can use the following table to find the corresponding measure of a mathematically similar shape. a) To work out the scale factor, SF, we need to divide the given side-length on the bigger shape by the corresponding side of the smaller shape. Doing so, we get, If we multiply the second equation by 2, we have two equations both with a 2x term, hence subtracting our new equation 2 from equation 1 we get, Then, to find x, we must multiply this value by the corresponding side-length of the smaller shape. So, we get The coefficients are the numbers before x and y, make the x coefficients the same by scaling up both equationsbegin{aligned}y&=2x-6\\ y&=\dfrac{1}{2}x+6 \\ \\ (y-y)&=(2x-\dfrac{1}{2}x)-6-6 \\ 0&= \dfrac{3}{2}x-12 \end{aligned} If we multiply the first equation by 2, we have two equations both with a 2y term, hence adding our new equation 1 and equation 2 we get, Learn an entire GCSE course for maths, English and science on the most comprehensive online learning AQA A Level Chemistry practice papers with mark schemes. A great way to practice for your exams. The profit from every set is reinvested into making free content on MME, which benefits millions of learners across the country.

Now, to get the area of the bigger shape, we must multiply the area of the smaller one by this scale factor. Doing so, we get Two shapes are said to be mathematically similar if all of the angles in the shapes are equal, but the shapes are not necessarily the same size. Now we have that the scale factor is \textcolor{blue}{3}, all we need to do to find x is multiply \textcolor{blue}{3} by the length of the corresponding side on the smaller shape. So we get Step 2: Now we must get the coefficients to match, in this case we can multiply the first equation by 2Therefore, to find the area of the smaller shape, we need to divide the area of the bigger shape by the area scale factor: 16. Doing so, we get There are 4 main types of graph transformation that we will cover. Each transformation has the same effect on all functions. From a humble beginnings of a dedicated individual adding free Maths content for all, to one of the country’s leading Maths, English and Science resources and a team committed to expanding on the good work, Maths Made Easy will continue to help more and more people find exceptional revision materials alongside expert private tutors.

Split the transformation up into 2 parts – firstly sketch y=3f(x) which is a stretch vertically by a scale factor of 3 (multiply the y-coordinates by 3:Now, if the scale factor for the side-lengths is \textcolor{red}{4}, then that means the scale factor for the volumes is: then there is a solution for us to find that works for both equations. These equations are called simultaneous for this reason. Step 1: Rearrange the linear equation to get one of the unknowns on its own and on one side of the equals sign. Now, if the scale factor for the side-lengths is \textcolor{red}{4}, then that means that the scale factor for the areas is: