About this deal
It is the current that a fuse is able to interrupt without being destroyed or causing an electric arc with unacceptable duration. The capacity of a fuse to operate between the lowest and the Rated Breaking Current code could be:
Fuses | Industrial Controls | Cef | CEF Fuses | Industrial Controls | Cef | CEF
In the glass fuses' code F is for fast blown the second number is the current, but I do not know what is the difference between L an AL (if there is any).
It's the watts dissipated in the fuse itself not the watts in the system. Therefore since the fuse has resistance (R) it's the current, which provides that power I
2Amp F2A F2AL 250v 10 Pieces Glass Fuse Fast Blow 20 x 5mm
F2A(237) * -F2A(37) * 0F2A(6) * 1F2A(7) * 2F2A(5) * 3F2A(2) * 4F2A(4) * 5F2A(1) * 6F2A(5) * 9F2A(1) * AF2A(12) * BF2A(17) * CF2A(13) * DF2A(37) * EF2A(21) * FF2A(4) * GF2A(5) * HF2A(12) * IF2A(2) * JF2A(5) * MF2A(1) * RF2A(5) * SF2A(2) * UF2A(1) * WF2A(1) F2A*(2112) * F2A-*(46) * F2A1*(82) * F2A2*(19) * F2A3*(5) * F2A4*(1) * F2A5*(24) * F2A6*(1) * F2A8*(2) * F2AA*(6) * F2AF*(2) * F2AP*(17) * F2AS*(21) * F2A_*(4)So if a fuse is rated for 12V DC and 20 A, this would be equal to 240 watts. If a different voltage is supplied, will this change the current at which the fuse will break? Does the fuse technically 'blow' at 240 watts?